Log(logx) by product rule ?
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When b is raised to the power of y is equal x:
b y = x
Then the base b logarithm of x is equal to y:
logb(x) = y
For example when:
24 = 16
Then
log2 (16) = 4
Logarithm as inverse function of exponential function
The logarithmic function,
y = logb(x)
is the inverse function of the exponential function,
x = b^y
So if we calculate the exponential function of the logarithm of x (x>0),
f (f -1(x)) = blogb(x) = x
Or if we calculate the logarithm of the exponential function of x,
f -1(f (x)) = logb(bx) = x
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