log(m+n)=logm+n show that log n =m/m-1
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Answer:
Step-by-step explanation:
log(m+n)= logm+ logn
log(m+n) = log(mn). [ loga+logb =log ab]
log on both sides geys cancel
then,
m+n = mn => m= mn -n
=> m = n(m-1)
=> n = m/m-1 [proved]
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