Question

log (MN) = logaM + logaN​

Answer 1

Answer:

log (MN) = logaM + logaN

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Answer 2

Answer:

Step-by-step explanation:

Let p = log ₐ M and q = log ₐ N

then M= a^p and N=a^q

MN=a^p*a^q=a^(p+q)

logₐ(MN) =logₐ{ a^(p+q) }

=(p+q)*log ₐ a

=(p+q) *1

=p+q

Putting the values of p and q we get

log ₐ (MN)  = log ₐ M + log ₐ N

Hence proved