Log of 6+2√5 to base √5+1 is
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6+2√5 = 5+1+2(1)(√5)
=(√5)^2+(1)^2+2(1)(√5)
=(√5+1)^2
log a^m = m loga
log a to base a =1
Log of 6+2√5 to base √5+1 is
= Log of (√5+1)^2 to base √5+1
= (2) Log of (√5+1) to base √5+1
=(2)(1)
=2
=(√5)^2+(1)^2+2(1)(√5)
=(√5+1)^2
log a^m = m loga
log a to base a =1
Log of 6+2√5 to base √5+1 is
= Log of (√5+1)^2 to base √5+1
= (2) Log of (√5+1) to base √5+1
=(2)(1)
=2
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