Question

log p-log q is same as​

Answer 1

Answer:

log p/q..................

Answer 2

log p - log q = log p/q

let logₐp = x => aˣ = p

logₐq = y => aʸ = q

logₐp - logₐq = x - y

Now from equations of exponentials , we have

aˣ/aʸ = aˣ⁻ʸ

Also p/q = aˣ/aʸ = aˣ⁻ʸ

Now, logₐ(p/q) => aˣ⁻ʸ = x - y

i.e., logₐ(p/q) = logₐp - logₐq

Thus, log p - log q = log p/q

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