Question

log p/q + log q/p = log(p+q) then
(a) (p+q)=2
(b) (p+q)=1
(C) (P-q)=0
(d) (p+q)=0
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Answer 1

we know , log a + log b = log a×b ..........(1)

and if log A = log B .......... (2)

then , A = B

so , according to question ,

log p/q + log q/p = log (p+q)

=> log p/q × q/p = log (p+q) ...... from (1)

=> log 1 = log (p+q)

=> p+q = 1 ....... from (2)