Math, asked by tatisrinivas1977, 9 months ago



log(p/q)+log(q/r)+log(r/p)=​

Answers

Answered by anindyaadhikari13
5

 log( \frac{p}{q} )  +  log( \frac{q}{r} )  +  log( \frac{r}{p} )

 =  log( \frac{p}{q} \times  \frac{q}{r}  \times  \frac{r}{p}  )

 =  log(1)

 =  log_{10}(1)

0

Hence, the answer is 0.

Answered by mysticd
4

 Given \: log \Big(\frac{p}{q}\Big) + log \Big(\frac{q}{r}\Big) + log \Big(\frac{r}{p}\Big)

/* By Logarithmic law */

\boxed{ \pink{ log m + log n = log ( m \times n ) }}

 = log \Big( \frac{ p}{q} \times \frac{ q}{r} \times \frac{ r}{p} \Big)

 = log \Big( \frac{pqr}{pqr}\Big)

 = log 1

 = 0

 \boxed {\blue {\because log_{a} 1 = 0 }}

Therefore.,

 \red{ log \Big(\frac{p}{q}\Big) + log \Big(\frac{q}{r}\Big) + log \Big(\frac{r}{p}\Big) } \green { = 0 }

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