log (p+q)(p-q) = 1
then log(p+q)(q2-p2)=?
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Answer:
log(p+q) (p-q)
p^2 -q^2 =1
then
log(p+q)(q^2 -p^2)
log(p+q)(-1)
log(p+q)=1
so
we know that
log(p+q)(q^2 -p^2)=-1
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