log (sec²x-tan²x) to the base cot221/2degree
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Answer:Tan (A/2) =Sin (A/2) / Cos (A/2)
Multiply and divide by 2 Cos (A/2)
Tan (A/2) = {2 Cos (A/2) Sin (A/2) } / { 2 Cos (A/2) Cos (A/2)}………….(1)
Sin A=2Sin(A/2) Cos(A/2) …..(2);
Cos A= Cos^2 (A/2)- Sin^2 (A/2)=2 Cos^(A/2) - 1
Cos A + 1=2 Cos^(A/2) …..(3);
==> Tan (A/2) = Sin A/(Cos A + 1) ……(comparing 1 with 2 & 3)
==>Cot (A/2) = (Cos A + 1) / Sin A
==> Cot(22.5) = (Cos 45 + 1) / Sin 45
==> Cot(22.5) = ((1 / √2 ) + 1)/ (1 / √2 ) = √2 + 1
Step-by-step explanation:
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