Math, asked by tamishnaik, 8 months ago

log(sin2x+3) diffrentiate w.r.t x

Answers

Answered by nandan2004

0

Answer:

log ( sin2x + 3)

d(log(sin2x + 3))/dx

1/(sin2x + 3) * (2cos2x + 0)

2cos2x / (sin2x + 3)

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