Math, asked by Anonymous, 6 months ago

Log $x^{5}$ -Log $x^{2}$ +Log $x^{3}$ =

Answers

Answered by tyrbylent

0

Answer:

6log x

Step-by-step explanation:

$logx^{5}$ - $logx^{2}$ + $logx^{3}$ = $log\frac{x^{5+3} }{x^2} = logx^{6}$ = 6 log x

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