Log v + log 3 = log pi + log 4 + 3 log r find v
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Answered by
17
Hi ,
It is given that ,
log v + log 3 = log π + log 4 + 3log r
******************
Here we are using ,
1 ) log m + log n = log mn
2 ) m log a = log a^m
************************
log 3v = log 4π + log r³
log 3v = log 4πr³
Remove log both sides of the
equation
3v = 4πr³
Therefore ,
v = ( 4/3 ) π r³
I hope this helps you.
: )
It is given that ,
log v + log 3 = log π + log 4 + 3log r
******************
Here we are using ,
1 ) log m + log n = log mn
2 ) m log a = log a^m
************************
log 3v = log 4π + log r³
log 3v = log 4πr³
Remove log both sides of the
equation
3v = 4πr³
Therefore ,
v = ( 4/3 ) π r³
I hope this helps you.
: )
Answered by
14
Heya,
_________________________________________________
⇒log v + log 3 = log π + log 4 + 3log r
⇒log v + log 3 = log π + log 4 + log r³
⇒log (v×3) = log (π × 4 × r³ )
⇒3v = 4πr³
⇒
i hope this will help you
-by ABHAY
_________________________________________________
⇒log v + log 3 = log π + log 4 + 3log r
⇒log v + log 3 = log π + log 4 + log r³
⇒log (v×3) = log (π × 4 × r³ )
⇒3v = 4πr³
⇒
i hope this will help you
-by ABHAY
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