Log * (x + 1) + log (x - 1) = 3 * log 2 + log 3 , then X = (a) 5 (b) log 10 (c) 2 (d)-5 3
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Answer:
Given:
log(x+1)+log(x−1)=log3
⟹log(x+1)(x−1)=log3
Using multiplication rule of logarithms,
loga+logb=logab
Thus, log(x
2
−1)=log3
⟹⇒x
2
−1=3
⟹⇒x=±2
But x
=−2∵x−1>0⇒x>1
∴x=2
Hence, option C.
Step-by-step explanation:
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