Question

log (x + 1) + log (x - 1) = log 24​

Answer 1

Answer:

$log(x+1)+log(x-1)=log(24)$

$=>log(x+1)(x-1)=log(24)$

$=> (x + 1)(x - 1) = 24$

$= > {x}^{2} - {1}^{2} = 24$

$= > {x}^{2} = 24 + 1$

$= > \sqrt{ {x}^{2} } = \sqrt{25}$

$= > x = 5$