Question

log
(x+1) +
log
(x-1) =
log
24​

Answer 1

Answer:

Step-by-step explanation:

log(x+1) + log(x-1) = log24​

$log(\frac{x + 1}{x - 1} ) = log 24\\\frac{x + 1}{x - 1} = 24\\x+1 = 24(x - 1)\\x +1 = 24x - 24\\23x = 23\\x = 1$