log(x+1) + log(x-1) = log 24
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Hey mate here is ur query....
_______________
log {(x+1)(x-1)} =log 24
As logA+logB = logAB
log {x²-1}= log 24
or x²-1 =24 As taking log on both sides
or x²= 25
or x=±5
But as we take the value of x under log so
x=5
______________
Hope this will help you...
_______________
log {(x+1)(x-1)} =log 24
As logA+logB = logAB
log {x²-1}= log 24
or x²-1 =24 As taking log on both sides
or x²= 25
or x=±5
But as we take the value of x under log so
x=5
______________
Hope this will help you...
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