Question

Log(x-1)+log(x+4)=log(3x+5) find x

Answer 1

matk it as brInliest

Answer 2

We know that
$log(x) + log(y) = log(xy)$
Hence
we get
$\\ = log((x - 1)(x + 4)) = log(3x + 5)$
taking antilog on both sides
$(x - 1)(x + 4) = 3x + 5 \\ {x}^{2} + 3x - 4 = 3x + 5 \\ {x}^{2} = 4 + 5 \\ x = \sqrt{9} \\ x = + 3 \\ or \\ x = - 3$
Here -3 is not defined for equation
Hence
x=3 is solution