log x+1 to the base 2
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MRK ME AS BRAINLIEST
Step-by-step explanation:
Given, log(x-1) + log(x+1) =log(1 to the base2)
We can write this as
log2(x-1) * (x+1) = 1
log2(x^2-1) = 1
x^2 - 1 = 1
x^2 = 2
x = root 2 and - root 2.
since log can be of negative value.
x = root 2.
Hope this helps!
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