Question

log(x-2)²=2-log(x+1)²

Answer 1

Answer:

x=0

Step-by-step explanation:

2 log (x-2) = 2- 2 log( x+2)

2 log (x-2) = 2 ( 1- log (x+2) )

log (x-2) = 1 - log ( x+2)

log ( x-2) + log ( x+2) =1

log {( x-2) (x+2)} = 1

log {(x^2) (2^2)}=1

log { (x^2)4} =1

log { (x^2)4} = log 0

x^2= 0÷4

x^2= 0

x=0