log(x-2)²=2-log(x+1)²
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Answer:
x=0
Step-by-step explanation:
2 log (x-2) = 2- 2 log( x+2)
2 log (x-2) = 2 ( 1- log (x+2) )
log (x-2) = 1 - log ( x+2)
log ( x-2) + log ( x+2) =1
log {( x-2) (x+2)} = 1
log {(x^2) (2^2)}=1
log { (x^2)4} =1
log { (x^2)4} = log 0
x^2= 0÷4
x^2= 0
x=0
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