Question

log(x^2-2x)= log (5x-12), find the value of x

Answer 1

Answer:

log(x^2-2x)=log(5x-12) -----equation 1

so by equating logarithms we get

x^2-2x=5x-12

x^2-2x-5x+12=0

x^2-7x+12=0

by quadratic equation we can equate to

(x-3) (x-4) = 0

so x=3 or x=4

x values are 3 and 4

by substituting 3 and 4 in equation 1 they satisfy the conditions