Question

log(x^2+81)-2logx=1​

Answer 1

Answer:

x=3

Step-by-step explanation:

log(x^2+81) - 2logx=1

=> log(x^2+81) - logx^2=1

=> log((x^2+81)/x^2=log10

=> (x^2+81)/x^2=10 [Taking anit-log]

=> x^2+81=10x^2

=> x^2-10x^2=-81

=> -9x^2=-81

=> x^2=-81/-9

=> x^2=9

=> x=3

Answer 2

Answer:

.......... hope it helps............