log( x + 2 )+ log( x- 2 )=log 5 find x
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LOG ( (x+2)(x-2)) = log 5
(x+2)(x-2) = 5
x^2 - 4 = 5
x^2 - 9 = 0
(x+3)(x-3)=0
x= -3 or x = 3
The solution x=-3 results in the log of a negative number,
and negative numbers are NOT in the domain of the log function.
The solution x=3 checks out! log(3+2) + log (3-2) = log(5) + log(1) = log(5) + 0 = log(5)
So x=3
Please mark brainliest answer
(x+2)(x-2) = 5
x^2 - 4 = 5
x^2 - 9 = 0
(x+3)(x-3)=0
x= -3 or x = 3
The solution x=-3 results in the log of a negative number,
and negative numbers are NOT in the domain of the log function.
The solution x=3 checks out! log(3+2) + log (3-2) = log(5) + log(1) = log(5) + 0 = log(5)
So x=3
Please mark brainliest answer
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