(log x)^2-(log y)^2=logx/y*log xy (prove the following)
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(log x)^2-(log y)^2
apply the formula of a^2-b^2 ie, (a+b)(a-b)
> [(log x)-(log y)][(log x)+(log y) ]
since, (log x)-(log y)=log(x/y) and
(log x)+(log y)=log xy
Hence,
[(log x)-(log y)][(log x)+(log y) ]=logx/y*log xy
hope it helps if so please mark it as brainliest
apply the formula of a^2-b^2 ie, (a+b)(a-b)
> [(log x)-(log y)][(log x)+(log y) ]
since, (log x)-(log y)=log(x/y) and
(log x)+(log y)=log xy
Hence,
[(log x)-(log y)][(log x)+(log y) ]=logx/y*log xy
hope it helps if so please mark it as brainliest
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