Question

log x/2 = log y/3, find value of y^4/x^6​

Answer 1

Answer:

HEY MATE

Step-by-step explanation:

logx/logy = 3/2, log(xy) = 5,

logx = 3/2 logy —————->eqn 1

log(xy) = log x + log y

log x + log y = 5, —————->eqn 2

Substitute eqn 2 in eqn 1!

3/2 logy + log y = 5,

5/2 log y = 5 , cancel 5 on both sides

log y = 2

log has base 10 so y is given by

y = 10 pow(2)

y = 100

Substitute y = 100 in eqn 2

log x + logy = 5

log x + log (100) = 5

log x + 2 = 5

log x = 3 , log has a base of 10 x given as

x = 10 pow(3)

x = 1000.

Hence x=1000, y = 100

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