Math, asked by anshj8066, 23 days ago

LOG(X^2/Y^3)=1&LOG(X^2Y^3)=7 THEN FIND VALUE OF XY​

Answers

Answered by QBrainlyA
0

Step-by-step explanation:

LOG(X^2/Y^3)=1&LOG(X^2Y^3)=7 THEN FIND VALUE OF XYLOG(X^2/Y^3)=1&LOG(X^2Y^3)=7 THEN FIND VALUE OF XYLOG(X^2/Y^3)=1&LOG(X^2Y^3)=7 THEN FIND VALUE OF XY

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