Question

log(x^2/y^x)+log(y^2/z^x)+log(z^2/x^y)=​

Answer 1

zero.....this is because the given expression can be rewritten as

log(x^2.y^2.z^2/xy.yz.zx) which becomes log((x^2.y^2.z^2/(x^2.y^2.z^2)) which is equal to log 1 whose value is zero ( I felt that there is a mistake in the question so i took it as above and solved it......if the question is as it is given then answer would be log(z/x) )

Answer 2

Answer:

6/"2#9"2=7 9"+'4!93@4@6@3"

Step-by-step explanation:

it's mythology