Question

Log (x-3) + log (x+1)= log 3 + log (x-1)
Please..

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

log a+ log b=log ab

log (x-3)+log(x+1)=log 3 +log(x-1)

log[(x-3)(x+1)] = log[3(x-1)]

hence

(x-3)(x+1)=3(x-1)

x^2-2x-3=3x-3

x^2-5x=0

x(x-5)=0

x=0 or 5

for x=0

log x-1 =log -1(not defined)

hence x=5