Question

log(x+3)+log(x-3)=log16 Solve for x

Answer 1

log(a) + log(b) = log(ab)
log(x+3) + log(x-3) = log[(x+3)*(x-3)] = log($x^{2}$ - $3^{2}$)

$x^{2}$ - 9 =16
x =5

Answer 2

Answer:

25

Step-by-step explanation:

Given : $\log(x+3)+\log(x-3)=\log16$

To Find:x

Solution:

$\log(x+3)+\log(x-3)=\log16$

Identity :$\log a+ \log b= \log(ab)$

So,  $\log((x+3)(x-3))=\log16$

$\log(x^2-3^2)=\log16$

$\log(x^2-9)=\log16$

$x^2-9=16$

$x^2=16+9$

$x=\sqrt{25}$

$x=5$

Hence value of x is 25