log(x+3)+log(x-3)=log16 Solve the quitio
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Here's your answer...
log (x+3) + log (x-3) = log 16
By the property log a + log b = log ab,
log (x+3) + log (x-3) = log (x+3)(x-3) = log (x²-9)
log (x²-9) = log 16
Taking antilog on both sides...
x²-9 = 16
x² = 25
x = 5
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Here's your answer...
log (x+3) + log (x-3) = log 16
By the property log a + log b = log ab,
log (x+3) + log (x-3) = log (x+3)(x-3) = log (x²-9)
log (x²-9) = log 16
Taking antilog on both sides...
x²-9 = 16
x² = 25
x = 5
[0110100101]... More questions detected... [010110011110]
//Bot UnknownDude is moving on to more queries
//This is your friendly neighbourhood UnknownDude
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