log X 32 = 10 find x
Answers
Answered by
1
log x 32 = 10
log x+ log 32 =10
log x + log(2)^5 = 10
log x +5×0.201 = 10
log x + 1.005 = 10
log x = 10-1.005 = 9.995
log x = 9.995
x = 10^9.995
= 10^5 + 10^0.995
= 9.3 × 10^5
log x+ log 32 =10
log x + log(2)^5 = 10
log x +5×0.201 = 10
log x + 1.005 = 10
log x = 10-1.005 = 9.995
log x = 9.995
x = 10^9.995
= 10^5 + 10^0.995
= 9.3 × 10^5
Similar questions