Question

log(x+4) +log(x-4)=1
Find x

Answer 1

Step-by-step explanation:

logx +log4 +logx -log4 = 1

logx + logx = 1

logx^2 =1

x^2 = 10

x =√ 10

Answer 2

Answer:

$log(x + 4) + log(x - 4) \\ = log((x + 4)(x - 4)) = 1$

we know that log10=1

Hence,

$(x + 4)(x - 4) = 10 \\ ( {x}^{2} - 16) = 10 \\ {x}^{2} = 26 \\ x = \sqrt{26}$