log(x+4)-log(x-4)=log2
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To solve logarithmic equation :-
log(x+4)-log(x-4)=log2
SOLUTION :-
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We know that,
log a - log b = log (a/b)
So,
log(x+4) - log(x-4)=log2
=> log [(x+4)/(x-4)]= log 2
Now, take the antilog on both side,
x + 4 / x - 4 = 2
=> x + 4 = 2(x - 4)
=> x + 4 = 2x - 8
=> x - 2x = - 8 - 4
=> -x = - 12
=> x = 12
ANSWER :- x = 12
______________________________
✝✝..HOPE IT HELPS YOU..✝✝
______________________________
HERE IS YOUR ANSWER...⤵⤵
______________________________
To solve logarithmic equation :-
log(x+4)-log(x-4)=log2
SOLUTION :-
______________________________
We know that,
log a - log b = log (a/b)
So,
log(x+4) - log(x-4)=log2
=> log [(x+4)/(x-4)]= log 2
Now, take the antilog on both side,
x + 4 / x - 4 = 2
=> x + 4 = 2(x - 4)
=> x + 4 = 2x - 8
=> x - 2x = - 8 - 4
=> -x = - 12
=> x = 12
ANSWER :- x = 12
______________________________
✝✝..HOPE IT HELPS YOU..✝✝
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Swarup1998:
Great answer! (:
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