Question

log_x 4+ log_x
+ loge 16 + log_x. 64 = 12​

Answer 1

Answer:

logx 4 + logx 16 + logx 64 = 12 ⇒ logx 4 + logx 42 + log, 43 = 12 ⇒ logx 4 + 2 logx 4 + 3 logx 4=12 ⇒ 6 logx 4 = 12 ⇒ logx 4 = 2 ⇒ logx 2x = 2 ⇒ 2 logx 2 = 2 ⇒ logx 2 = 1 ⇒ logx 2 = log2 2 On comparing, x = 2Read more on Sarthaks.com - https://www.sarthaks.com/735897/find-the-value-of-x-from-following-equation-logx4-logx16-logx64-12