Question

log(x+4)-log7=3log2-log(x+5​

Answer 1

Answer:

x=3,x=-12

Step-by-step explanation:

log(x+4)+log(x+5)=(log2)^3+log7

log((x+4)(x+5))=log8+log7

log(x2+5x+4x+20)=log(7×8)

log(x2+9x+20)=log(56)

x2+9x+20=56

x2+9x-36=0

x2+12x-3x-36=0

x(x+12)-3(x+12)=0

(x-3)(x+12)=0

x=3,x=-12

Answer 2

Step-by-step explanation:

log(x+4)-log7=3log2-log(x+5)

log(x+4)+log(x+5)=3log2+log7

log{(x+4)(x+5)}=log2³+log7

log(x²+4x+5x+20)=log8+log7

log(x²+9x+20)=log(8×7)

log(x²+9x+20)=log56

x²+9x+20 = 56

x²+9x-36=0

x²+12x-3x-36=0

x(x+12)-3(x+12)=0

(x-3)(x+12)=0

x-3=0 ; x+12=0

x=3 ; x=-12

.....666.....