log x (4x-3) = 2 solve the following equations
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amey51:
how to solve ???
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Hi mate ,let the base be x then solve you get x= 1,3 .
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given, = 2
or, 4x - 3 = x²
or, x² - 4x + 3 = 0
or, x² - 3x - x + 3 = 0
or, x(x - 3) -1(x - 3) = 0
or, (x - 1)(x - 3) = 0
or, x = 1, 3
for log to be defined,
4x - 3 > 0
or, x > 3/4
hence, x = 1 and 3, both are solutions of given equation.
hence, answer is 1 and 3.
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