Question

log(x-9) base 10+ log x base 10 = 1 then x is

Answer 1

Step-by-step explanation:

log(x-9) base 10+ log x base 10 = 1

log(x−9)+log(x)=1

log( {x}^{2} - 9x) = log(10)log(x ^2 −9x)

=log(10){x}^{2} - 9x

= 10x ^2 −9x

=10{x}^{2} - 9x - 10

= x^2 −9x−10=0

{x}^{2} - 10x + x - 10 = 0

x ^2−10x+x−10=0

x(x - 10) + 1(x - 10) = 0

x(x−10)+1(x−10)=0

(x - 10)(x + 1) = 0

(x−10)(x+1)=0

so X = 10 , -1 but -1 cannot satisfy equation hence

X = 10