Question

log (x-9) base 10+logx base 10 = 1 then x = ?

Answer 1

Answer:

$log(x - 9) + log(x) = 1$

$log( {x}^{2} - 9x) = log(10)$

${x}^{2} - 9x = 10$

${x}^{2} - 9x - 10 = 0$

${x}^{2} - 10x + x - 10 = 0$

$x(x - 10) + 1(x - 10) = 0$

$(x - 10)(x + 1) = 0$

so X = 10 , -1 but -1 cannot satisfy equation hence

X = 10 only answer.

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mark BRAINLIEST if you think

Answer 2

Answer:

log(x - 9) + log(x) = 1log(x−9)+log(x)=1

log( {x}^{2} - 9x) = log(10)log(x

2

−9x)=log(10)

{x}^{2} - 9x = 10x

2

−9x=10

{x}^{2} - 9x - 10 = 0x

2

−9x−10=0

{x}^{2} - 10x + x - 10 = 0x

2

−10x+x−10=0

x(x - 10) + 1(x - 10) = 0x(x−10)+1(x−10)=0

(x - 10)(x + 1) = 0(x−10)(x+1)=0

so X = 10 , -1 but -1 cannot satisfy equation hence

X = 10 only answer.