Question

log x base 3= log 16 base 9 , x+1 =?

Answer 1

Answer:

To begin with let's make sure that the bases are the same so write log base 9 of x as a base of 3

1/2log base 3 of x + log base 3 of x =6

As the multiplication law of logarithms states that when it's addition you multiply and vice versa:log base c of xy=log base c of x + log base c of y

log base 3 of ( x1/2×x)=6

36=729

x1/2×x=729 since it's multiplication you add the powers so 1/2 +1 =3/2

x3/2=729

So square 729. 7292=531441. Now take a cube root. Cube root of 531441 is 81

X=81

Answer 2

Answer:

x=4

Step-by-step explanation:

$log_{3}(x) = \frac{ log_{3}(16) }{ log_{3}(9) } \\ = \frac{ log_{3}( {4}^{2} ) }{ log_{3}(3^{2} ) } \\ = \frac{ 2 log_{3}(4) }{2 log_{3}(3) } \\ log_{3}(x) = log_{3}(4) \\ x = 4$

Mark my answer as brainliest.

Cheers!