Question

(log x)^cosx प्रदत्त फलनों का x के सापेक्ष अवकलन कीजिए

Answer 1

$dy/dx = (log x)^{Cosx} ( \frac{Cosx}{xlogx} - Sinx log(log x))$  यदि  $y = (log x)^{Cosx}$

Step-by-step explanation:

dy/dx ज्ञात कीजिए

$y = (log x)^{Cosx}$

$log y = log( (log x)^{Cosx})$

log y = Cosx log ( log x)

(1/y)  dy/dx  =  - Sinx log(log x)  + Cosx  (1/logx) (1/x)

=> (1/y)  dy/dx  =  - Sinx log(log x)  + Cosx/xlogx

=> dy/dx  = y  (Cosx/xlogx -  Sinx log(log x))

=> $dy/dx = (log x)^{Cosx} ( \frac{Cosx}{xlogx} - Sinx log(log x))$

और अधिक जानें :

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