log(x)-log(2x-3)=1then x=?
Answers
Answered by
1
Log(x)-log(2x-3)=1
Log(x/2x-3)=1
x/2x-3=10
x=20x-30
30=19x
x=30/19
Answered by
1
Hey!!!...Here is ur answer
log (x)-log (2x-3)=1
=> log (x)-log (2x-3)=log10
=> logx/2x-3=log10
Comparing both sides
=> x/2x-3=10
=> x=10 (2x-3)
=> x=20x-30
=> 19x=30
=> x=30/19
Hope it will help you
log (x)-log (2x-3)=1
=> log (x)-log (2x-3)=log10
=> logx/2x-3=log10
Comparing both sides
=> x/2x-3=10
=> x=10 (2x-3)
=> x=20x-30
=> 19x=30
=> x=30/19
Hope it will help you
Similar questions