Question

Log x = log 3 + 2 log 2- (3/4) log 16. the value of x is: op 1:

Answer 1

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solution:--

log x= log 3+ 2 log 2 - (3/4)log 16.
log x = log 3 + 2 log 2 - (3/4) log 2^4.
log x = log 3 + 2 log 2 - (3*4)/4 log 2.
log x = log 3 + 2 log 2 - 3 log 2.
log x = log 3 - log 2. 
log x = log 3/2.
Therefore, by equating, x = 3/2.