Question

Log X/ log 5= log y ^2/log 2= log 9/1/3

Answer 1

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Now..
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$= > \bf \frac{ log(x) }{ log(5) } = \frac{ log( {y}^{2} ) }{ log(3) } = log( \frac{9}{ \frac{1}{3} } ) \\ \\ or. \: \: log( x ) - log(5) = log( {y}^{2} ) - log(3) = log( {3}^{3} ) \\ \\ \\ so \\ \\ or. \: \: \bf log(x) - log(5) = log( {3}^{3} ) \\ \\ or. \: log(x) = log( {3}^{ 3} ) + log(5) = log( {3}^{3} \times 5) \\ \\ or. \: \bf \: x = {3}^{3} \times 5 = 135 \\ \\ \\ and \\ \\ \\ or. \: \bf \: log( {y}^{2} ) - log(3) = log( {3}^{3} ) \\ \\ or. \: \: log( {y}^{2} ) = log( {3}^{3} ) + log(3) = log( {3}^{3} \times 3) \\ \\ or. \: {y}^{2} = {3}^{4} \\ \\ or. \: \bf \: y = {3}^{2} = 9$
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Answer 2

Step-by-step explanation:

log x /log 5 = logy^2/log2 = log 9/1/3

log x - log5 = log y^2 - Log2 = log 3^3

value of x

log x - log5 = log 3^3

log x = log 27 + log 5

x = (27×5) = 135

value of y

logy^2-log2=log27

logy^2 = log27 + log 2

y^2 = (27×2) = 54

y = root over 54