log x-log √x=2/log x
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Answered by
12
Hi ,
log x - log √x = 2/logx
=> logx -( 1/2 )log x = 2/logx
=> (1/2) logx = 2/logx
=> ( logx )² = 2²
log x = 2
I hope this helps you.
: )
log x - log √x = 2/logx
=> logx -( 1/2 )log x = 2/logx
=> (1/2) logx = 2/logx
=> ( logx )² = 2²
log x = 2
I hope this helps you.
: )
Answered by
8
Given : log x - log √x = (2/log x)
= > log x - log(x)^1/2 = (2/log x)
We know that log (a^m) = m log a
= > log x - (1/2) log x = (2/log x)
= > log(x)^2 - (1/2) log x * log x = 2
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Let a = log x.
= > a^2 - (1/2) a^2 = 2
= > 2a^2 - a^2 = 4
= > a^2 = 4
= > (a)^2 = (2)^2
= > a = 2
Therefore, log x = 2.
Hope this helps!
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