Question

log x + log y= log(x+y) ​

Answer 1

Step-by-step explanation:

Consider:

log(x+y)=logx+logy

Put x=y=1

⟹log(1+1)=log1+log1

⟹log2=0+0

⟹0.3010=0Contradiction

Hence, log(x+y)≠logx+logy

P.S. - You must be confusing this with the product property of logarithms which is:

loga(x⋅y)=logax+logay

Thanks!

Answer 2

Answer:

If log x +log y = log(x+y), y can be expressed as

a) x-1 b)x c)x/x-1

Step-by-step explanation:

hope you will like it