Question

Log ( x square-2x)-log (4 -x)= log3 find the x

Answer 1

hope it will help you:-)

Answer 2

Step-by-step explanation:

$log( {x}^{2} - 2x ) - log(4 - x) = log(3) \\ log( \frac{ {x}^{2} - 2x }{4 - x} ) = log(3) \\ {x}^{2} - 2x = 3(4 - x) \\ {x}^{2} - 2x + 3x - 12 = 0 \\ {x}^{2} + x - 12 = 0 \\ {x}^{2} - 3x + 4x - 12 = 0 \\ x(x - 3) + 4(x - 3) = 0 \\ (x + 4)(x - 3) = 0 \\ x = - 4 \\ x = 3$

HOPE IT HELPS........