Question

log x to the base 9+log x to the base 3 =3/2 find x​

Answer 1

Answer:

Step-by-step explanation:

$\frac{logx}{log9} + \frac{logx}{log 3} = \frac{3}{2}$

$\frac{log x}{3log 3} + \frac{3logx}{3log 3} = \frac{3}{2}$

$\frac{4logx}{3log3} = \frac{3}{2}$

$\frac{4logx}{3*0.47} = 1.5$

$4 logx = 2.11$

$logx = 0.52$

$x = alog(0.52)$