Question

log(x-y÷3)=1÷2(logx+logy)=x^2+y^2=11xy​

Answer 1

Answer:

log(x-y)/3 =log(√xy)

(x-y)/3=√xy

x-y=3√xy

squareing both sides we get

x^2+y^2-2xy=9xy

x^2+y^2=9xy+2xy=11xy

Answer 2

Answer:

hey mate please refer to the attachment