Question

log (x+y) = log 3 + ½log x + ½log y then prove that x² + y²=7xy



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Answer 1

Answer:

Mark brainliest please

Step-by-step explanation:

log(x+y)=log3+1/2logx+1/2logy

log(x+y)=log3+logx^1/2+logy^1/2 (as mlogn=logn^m)

log(x+y)=log(3*x^1/2*y^1/2) (as loga+logb+logc=log(abc))

hence(x+y)=(3*x^1/2*y^1/2)

squaring both sides

(x+y)^2=9xy

x^2+y^2+2xy=9xy

x^2+y^2=7xy hence proved