log(x-y) =logx-logy then x
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HERE IS YOUR ANSWER
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PLEASE MAKE AS BRAINLIEST
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pornimv:
now i have changed it
Answered by
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Hey guy here is ur answer :-______________________________________________________
log(x-y) =logx-logy
Multiply e^x on both sides.
e^log(x-y) =e^logx-logy
Cancel log on both sides
x-y=x/y
x=(x+y^2)/y
Hope it helps u
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