Question

log (x/y)= x+y, dy/dx may be found to be ​

Answer 1

Step-by-step explanation:

$log( \frac{x}{y} ) = x + y \\ logx - logy = x + y \\ \frac{1}{x} - \frac{1}{y} \frac{dy}{dx} = 1 + \frac{dy}{dx} \\ \frac{dy}{dx} (1 + \frac{1}{y} ) = \frac{1}{x} - 1 \\ \frac{dy}{dx} ( \frac{1 + y}{y} ) = \frac{1 - x}{x} \\ \frac{dy}{dx} = \frac{y(1 - x)}{x(1 + y)} \\ \\ hope \: it \: will \: help \: you.$